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Using this redox equation:
Mn(OH)2(s) + MnO4-(aq) → MnO42-(aq) When the equation is balanced with smallest whole number
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Answers (1)
3e- + 2H2O + Mn(OH)2(s) → MnO4^(2-)(aq) +6H + 4e- 1e- + MnO4-(aq) → MnO4^(2-)(aq) ----this is what I got after balancing the charges with e- but this maybe completely wrong, I took a guess. The choices given are: 4, reactant side 4, product side 6,
