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oobleck
Questions and answers by visitors named
oobleck
Questions (28)
I have been thinking about the walking surveyor, and here is a less complicated solution (also, correct, as it happens - the
3 answers
370 views
I ran across this one the other day. See what you can make of it.
Find the integral of e<sup><sup>cosx</sup></sup>sinx -
3 answers
1,066 views
One of the events at the circus starred Gabriella the Human Cannonball. On Saturday she performed in four shows. Shot from a
7 answers
1,522 views
What is 2+2x4x6-3x2+1 equal
1 answer
303 views
PLEASE HELP ME!
What is the x-coordinate where the graph of the function represented by the Maclaurin series 1 minus 2 times x
3 answers
993 views
Sorry - I looked at this earlier, but had to go. Here's how to fix things, if you haven't already done so.
Your function
1 answer
236 views
It took me a while to figure this out, but here goes.
The Problem was: Inside a right circular cone with base radius 5 and height
4 answers
545 views
Hey Yo need some Help
Explain how nerve impulses travel and what occurs during a reflex arc.
1 answer
359 views
If I have one brain cell, and add the other one that I don't have, what have I got?
4 answers
158 views
Have the students on this site gotten stupider recently? I never used to see post after post after post from the same user, all
1 answer
157 views
I CANT FIND THE RIGHT ANSWER PLEASE HELP ME BOT THANKS AND IM UGLY
Four friends shared 1 2 of one carton of orange juice and 1 4
9 answers
301 views
I see you have stopped allowing followup comments. This makes it impossible for us to correct your many mistakes in the math
3 answers
46 views
The question was:
Suppose a parabola has vertex (5, –3) and also passes through the point (6, 1). Write the equation of the
3 answers
63 views
The question was:
What is the solution to the following system x-y+z=-1 x+y+3z=-3 2x-y+2z=0 Both bots got it wrong. The correct
3 answers
49 views
The question was:
write the equation of the given parent graph with the points, (5,-2), (6,0), The Bot determined that the
3 answers
79 views
Both bots got this wrong:
Which of the following re-expresses the negative square root -6√-20 as a complex number in the
3 answers
152 views
The question was:
Take g= 10 m/s2. A stone propelled from a catapult with a speed of 50 m/s attains a height of 100 m. Calculate:
3 answers
40 views
The question was:
What value falls in the solution set of the inequality −3(4k+1)<15?(1 point) −4 −5 −3/2 −1 Both bots
3 answers
69 views
the question was:
Two penguins are standing at the South Pole. One walks northwards, and the other turns and walks in the
3 answers
49 views
the question was:
evaluate (−3/5) × (5/16) × (7/12) ÷ (−3/16) ×( −5/7) Somehow, both bots blew it. Bot got -1/12
3 answers
44 views
All three of the Bots got this wrong:
If the multiplicity of a linear factor is even, then the graph passes through the x-axis at
3 answers
89 views
All three of the Bots got different answers to this:
Which of the following is a zero of x^3−5x^2−2x+24 , given that x−3 is
3 answers
46 views
The question was:
1/2 log 8 base 4 + log 32 base 4 - log 2 base 4 And of course, the Bot managed to mess this up. It wrote base
3 answers
70 views
the question was:
what can i use as a fraction sign? Odd that none of the bots mentioned the ÷ symbol ...
3 answers
38 views
the question was:
(225^2 - 2*225*16π + 256π^2)/(16π^2) = 16+h^2 The Bots all missed it, since the solution is as follows: (225
3 answers
82 views
To @alyssa!
learn how to type math! Instead of this nonsense: 48−−√ Just type √48 It's much easier to read.
1 answer
53 views
.;;;;;
1 answer
26 views
Have a good weekend
3 answers
26 views
Answers (40,186)
also 12(x-2)^2
since cos(kx) has period 2π/k, we need 2π/k = 2π/3, so k = 3 so our function is C. y = 2 cos 3θ
cos^2(θ) / (1 - sin(θ)) = (1 - sin^2θ)/(1-sinθ) = 1+sinθ
so very wrong! 2 sin θ cos θ + √3 cos θ = 0 cosθ (2sinθ + √3) = 0 so we have either cosθ = 0 so θ = π/2 or 3π/2 or (2sinθ + √3) = 0 sinθ = -√3/2 so θ = 4π/3 or 5π/3
also, from the original equation, x ≠ -3, -4, 6
wrong. It is (x^2 - 1) / (x + 3)
That's not what I get: (x + 5)/(8x) = 1/4 + 3/(2x) (x+5) = 2x + 12 x = -7
wrong - 9-8 = 1, not 2
correct logic, but wrong final results 275 * (1.032)^13 = 275 * 1.506 = 414.16
but √45 = 3√5
sin 180° = 0
wrong. 210°, where sin is negative
wrong! sin pi/4 = 1/√2 tan pi/4 = 1 or, solving it your way, tanθ = sinθ sinθ/cosθ = sinθ sinθ = sinθ cosθ sinθ (1-cosθ) = 0 cosθ = 1 θ = all multiples of 2pi or, sinθ = 0, at all multiples of pi
sinθ = tanθ = 0 at all multiples of pi
I think you meant: θ = ((2πr)/(2πl)) * 360 θ = ((8)/(8.544)) * 360 θ = (8/8.544) * 360 θ ≈ 337.1 degrees since the height is so small compared to the base radius, it means you have almost the entire original circle.
life is like a simile.
wrong - they mostly use "de"
how you justified this step I'll never know: (2^15) / 16 = 2 In fact, (2^15) / 16 = 2^15 / 2^4 = 2^11
wrong. 4√6 / √30 = 4√6 / √6√5 = 4/√5
wrong. the height h can be found using 1/2 * 14*h = 125 h = 125/7 So the two congruent sides each have length sqrt(7^2 + (125/7)^2) = 19.18
choose E
what a lot of work, to arrive at the wrong answer! (x^2 - 16)/(2x^2-9x+4) ÷ (2x^2 + 14x + 24)/( 4x+4) = (x+4)(x-4) / (x-4)(2x-1) ÷ 2(x+4)(x+3) / 4(x+1) = (x+4)/(2x-1) * 2(x+1) / (x+4)(x+3) = 2(x+1) / (2x-1)(x+3)
cone: diameter = height, so h = 2r. So, since its volume is 4, we have 1/3 πr^2(2r) = 2/3 πr^3 = 4 for the hemisphere, V = 2/3 πr^3 = 4 so the total volume is 8
1/18 + 1/x = 1/12 1/x =1/36 x = 36
no, bozo, it's 25t+3t=9
no, your choice models the scenario where Mike is walking away from Jamal.
the next number is 9, but not for the reason you showed. the differences decrease by 2 each time. The sequence is ... 81-17=64-15=49-13=36-11=25-9=16-7=9
surely you meant 54+5 = 59
clearly, we need a quadratic function, so let's use h(t) = -0.2t^2 + 2t max height of 5 ft is achieved at t = 5 s the ball hits the ground at t = 10 s
a cone of radius r and height 2r has volume 1/3 πr^2 * 2r = 2/3 πr^3 since a sphere of radius r has volume 4/3 πr^3, two cones will fill the same volume
the user asked for radical forms, but since the question did not contain any, I guess they botched it somehow.
It is easy to see that neither of the given points lies on the line 3x-y = -11.
a better domain would be 0 ≤ t ≤ 5.35, since the rock hits the ground at t=5.35
"exact area of the major segment is approximately" makes no sense. In fact, the exact area is 49π - (5π/6) * 7^2 / 2 = 343/12 π
72s - 99 = 9(8s-11)
Josh has 75 pens 10*7 + 5 = 75 9*8 + 3 = 75
the question has been corrupted, since x + 1 = (2x + 3) -2 = x
if you write it correctly, it does have infinitely many solutions: (12x + 32)/4 = 3x + 8
wrong again (4 × 10^4)/(6 × 10^6) × (3 × 10^-2) = (4*3)/6 x 10^(4-6-2) = 2x10^-4
sorry - 4/2 = 12/6
so you're saying that 1 is greater than 15?
wrong. B. 11a^2-12/30a^3b^2
wrong again. The sequence continues from -17, with -17-10 = -27 -27-12 = -39 -39-14 = -53
as given, we do not have a geometric series. I suspect the user meant 4, -12, 36, ... where r=-3 so the 4th term is -108
any one of those except B could be correct, depending on the expression. the amplitude is always positive; a not necessarily
that expression is a bit too trivial. I suspect the user meant √(x + 4) - 3 = 7 √(x+4) = 10 x+4 = 100 x = 96
23 feet
we know that a_5 = 3, so a_7 = 3-8 = -5
tan(1/2 x) = f tanx = 2f/(1-f^2) sinx/cosx = 2f/(1-f^2) sinx = cosx * 2f/(1-f^2) now, since sec^2(x) = 1 + tan^2(x), we have cos^2(x) = 1/sec^2(x) = 1/(1 + (2f/(1-f^2))^2) sinx = 2f/(1-f^2) √(1/(1 + (2f/(1-f^2))^2) = 2f/(1-f^2) * (f^2-1)/(f^2+1) =
wrong again. The distances from (-4,-3) are: 1. (-4,16): 19 2. (5, -3): 9 3. (-13, -3): 9 4. (-4, -13): 10 5. (-4, 6): 9 so, 2,3,5
