Find the restrictions:
how to solve problem
1. y = 3- sqrt(2x-8)
x => 0
2. y = 9-sqrt(x -2)
x =>0
#1
2x-8 ≥ 0
2x≥ 8
x ≥ 4
#2
x-2 ≥ 0
x ≥ 2
where is 3 goes?
To find the restrictions for each equation, we need to analyze the domain of the square root function within each equation.
1. y = 3 - sqrt(2x - 8)
To determine the restrictions for this equation, we need to find the values of x that make the expression inside the square root function equal to or greater than zero.
2x - 8 ≥ 0
2x ≥ 8
x ≥ 4
Therefore, the restriction for this equation is x ≥ 4, which means that the value of x must be greater than or equal to 4.
2. y = 9 - sqrt(x - 2)
Similarly, we need to find the values of x that make the expression inside the square root function equal to or greater than zero.
x - 2 ≥ 0
x ≥ 2
Therefore, the restriction for this equation is x ≥ 2, which means that the value of x must be greater than or equal to 2.