Ca = 0.75 , Cb = 0.735, and Ka = 7.87044 × 10 6

volume of acid is 100 mL.

What is the volume of base at the equiva- lence point of this titration?

To find the volume of base at the equivalence point of this titration, we need to use the concept of stoichiometry and the balanced chemical equation for the reaction between the acid (Ca) and base (Cb).

The balanced chemical equation for the reaction can be written as:
Ca + Cb → Products

Given that the volume of acid (Ca) is 100 mL and its concentration is 0.75, we can calculate the number of moles of acid (nCa) using the formula:
nCa = concentration x volume
nCa = 0.75 x 0.1 (since the volume is given in mL, we convert it to liters by dividing by 1000)
nCa = 0.075 moles

Since the stoichiometry of the reaction is 1:1 between Ca and Cb, the number of moles of base (nCb) at the equivalence point will also be 0.075 moles.

To find the volume of base (Cb), we can use the formula:
volume = moles / concentration

Given that the concentration of base (Cb) is 0.735, we can calculate the volume of base (Cb) at the equivalence point:
volume = 0.075 / 0.735
volume ≈ 0.102 liters (or 102 mL)

Therefore, the volume of base at the equivalence point of this titration is approximately 102 mL.