What is the maximum kinetic energy of an ejected electron if silver metal is irradiated with 228-nm light? The threshold wavelength for a silver metal surface is 267 nm.
To find the maximum kinetic energy of an ejected electron, we need to consider the energy of the incident light and the threshold wavelength for the metal surface. Here's how you can calculate it:
1. Determine the energy of the incident light using the formula:
E = hc/λ
where E is the energy of the light, h is Planck's constant (6.626 x 10^-34 J·s), c is the speed of light (3.00 x 10^8 m/s), and λ is the wavelength of the light in meters.
In this case, the incident light has a wavelength of 228 nm, so we need to convert it to meters:
λ = 228 nm = 228 x 10^-9 m
Now, substitute the values into the formula to find the energy:
E = (6.626 x 10^-34 J·s)(3.00 x 10^8 m/s) / (228 x 10^-9 m)
2. Calculate the threshold energy using the threshold wavelength of 267 nm. Follow the same steps as above to find the threshold energy, but substitute the threshold wavelength:
λ = 267 nm = 267 x 10^-9 m
3. The maximum kinetic energy of the ejected electron can be found by subtracting the threshold energy from the energy of the incident light:
Kinetic energy = E - threshold energy
Following these steps, you can calculate the maximum kinetic energy of the ejected electron when silver metal is irradiated with 228-nm light.