Questions LLC
Login
or
Sign Up
Ask a New Question
Box Jellyfish
Questions and answers by visitors named
Box Jellyfish
Answers (4)
If you won't revise anything it would be hard ofcourse...
given, m1 = 2kg ; m2 = 8kg; coefficient of friction = 0.3; F = 10 N For m1: m1*g = N m1*a1 = F-F(friction) = F- (coefficient of friction)*N = F- μ*m1*g a1 = F/m1 - μ*g = 10/2 - 0.3*9.8 = 2.06 m/s² For m2: m2*a2 = F(friction) a2 = F(friction)/m2=
Frictional force after calculation = 30N Coefficient of friction = 0.15
mass of block = 10Kg F = (coefficient of friction)* mg =0.40*10*10 =40N By F = ma a = F/m = 40/40 = 1 m/s^2
