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CLETUS MATTHEW
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CLETUS MATTHEW
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28t=a+27d since 28t=-5 ,a=31 -5=31+27d -27d=31+5 -27d=36 d=-36/27 d=-4/3
x=a and x=ky [x=a+ky] when x=7 ,y=5 x=a+ky 7=a+5k a+5k=7 eqn [1] when x=8,y=7 x=a+ky 8=a+7k a+7k=8 subtract eqn 1 from eqn 2 a-a+7k-5k=8-7 2k=1 k=1\2 substitute k=1\2 in eqn 1 a+5k=7 a+5[1/2]=7 a+5/2=7 a=7-5/2 a=14-5/2 a=9/2 [x=9/2+1/2] find x when y=11
