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GanonTEK
Questions and answers by visitors named
GanonTEK
Answers (168)
(f ∘ g)(x) = f(g(x)) f(g(x)) = 8(6x - 14) g(x) could be 6x - 14 and f(x) could be 8x
t = -4 doesn't work for the question you posted there. Is there a bracket missing? I did it both with and without and neither work. I got 3t^2 + 2t + 6 = 6 That then gives me t = 0 or t = -2/3
when f'(x) > 0 it's increasing when f'(x) < 0 it's decreasing vertical asymptotes: put the denominator equal to zero and solve for x. So when x^2 - 9 = 0 (Just an extra bit of info: for horizontal asymptotes divide by the highest power of x and then apply
You're welcome
You want dP/dt, you have dV/dt so what do you need? dP/dt = dV/dt * something the something is dP/dV so that the dVs cancel and so you get dP on top. You have to write PVb=C as P = and then differentiate that to get dP/dV. You should be able to substitute
Leslie: 4.5 laps = 0.75 hrs x laps = 1.00 hrs Find x (the number of laps Leslie does in an hour) Kayla 3.5 laps = 0.75 hrs y laps = 1.00 hrs Find y (the number of laps Kayla does in an hour) x - y is the difference or extra that Leslie will run in an hour
Starting at 8 keep adding 8s and write out the list of numbers. With 12, start at 12 and keep adding 12s to it and write out that list Once you see the first number that appears in both lists that's the lowest common multiple. Any other numbers that also
Well one reason is that the energy of the collision might be lower than the activation energy.
Use the formula a(n) = a + (n-1)*d for the arithmetic series part. n is the number of the term. E.g. n = 1 is the 1st term, n = 4 is the 4th term, etc. 72 = a + (21 - 1)d You can find a in terms of d. Use that then to get the 1st, 5th and 13th terms in
Change Sin^2(x) into 1-cos^2(x), substitute it in, tidy it up and you'll get a quadratic of the form aCos^2(x) + bCos(x) + c = 0 Then let, say, y = Cos(x) then and you get ay^2 + by + c = 0 which is a more normal quadratic. Solve that for y and put your
The good thing about simultaneous equations is that you can check your own answers by substituting them back into the equations. I just tried that and your answer didn't work for either equation.
cos^2(β)-cot^2(β) can be simplified futher. cot = 1/tan = cos/sin
Not A Median is the middle number. When you have an even number of data values you have to get the average of the two middle values instead.
It is 6% per quarter though. You don't have to divide by 4. It's not 6% per annum. Even if it was you can't just divide by 4. You have to use P(1+r)^t = P(1+R)^T r = first rate t = 1 (usually) R = second rate T = amount of these time periods in t E.g. 6%
You need an equation of motion v^2 = u^2 + 2aS v = final velocity u = initial velocity a = acceleration s = displacement Watch your units. The velocity is in km/h and your displacement is in cm and you want the answer in m/s^2
Pick any three values for x and find the three corresponding values of y for the values you choose. Then right in the form (x,y)
*makes the total increase 32.35% not 30% as you have
I see where you went wrong. If, say, you increased the price of something by 20% that's not the same as if you increased the price by 10% today and then 10% again tomorrow. If it was €100 to begin with 10% would be €10. Your total is now €110 If you
Not B How do you go from -2 to -12 and from -12 to -72? Is there something you can add/subtract/divide/multiply that would work for both?
Real roots would be x = 1 or x = -1 Complex roots would be x = i or x = -i or if the complex number, for example, was 4 - 7i then x = 4 - 7i would be the root if that was the solution to the question.
conservation of momentum m1u1+m2u2=m1v1+m2v2 m1 = mass of first thing (girl) m2 = mass of second thing (book) u1 = initial velocity of first thing (girl) u2 = initial velocity of second thing (book) v1 = final velocity of first thing (girl) v2 = final
Universal indicator paper, Phenolphthalein, methyl Orange, pH meter. Mix some with some acid and you should get salt and water. You can use Cobalt Chloride paper to test for water and evaporate to get the salt.
Oh yeah, I forgot I could simplify too. Thanks Reiny!
Reiny, there are 3 months in a quarter of a year so I'm unsure why you divided by 4 unless you were trying to get the monthly rate but that's not how you get the monthly rate and there aren't 16 months in 4 years. Present value of 1st 2400 is 2400 Present
P(Green) = 5/30 = 1/6 P(yellow after green) = 8/29 (as one has been taken away) Probability of both of these happening - so green and yellow afterwards is multiply the two probabilities together together (1/6)*(8/29) = 8/174 Which is the same as Tia said
Option one: $24,000 F = P(1+r)^t F = 24,000(1+0.06)^16 16 because the rate is per quarter of a year and there are 16 quarters in 4 years Option 2: 2400 every quarter for 4 years (so 16 of these 2400 gifts in total) 1st $2400 gift will be in for the full 16
F = P(1 + r)^t F = final amount P = Principal amount r = rate (in decimals) t = time
call the number x and make two equations - one from each of the contitions - and put them equal to each other and solve for x
Kinetic Energy = (1/2)*m*v^2 maybe? 25,000 = 0.5*m*5^2 Solve for m then.
For part a) Just substitute in t into the equation you have. x = (1.09)cos(3.11πt) x is the displacement and this will come out as an answer in meters. 1.09m is your max amplitute (the number in front of the cos). If you get a negative answer that just
Use F = ma on each mass If you draw it out it helps a great deal as you can fill in all the forces. Gravity acts on both and tension acts on both in the opposite direction to gravity in both cases. The 10kg particle is going to win out so it will fall
Multiply the numbers. Then use 16 oz = 1 lb to get the units you want I feel like a piece of info is missing like the number of pencils in a box.
oh and then convert the mass from tons into pounds
no, that E-7 means 10^-7 not -10^7
Ah, but while all rectangles and squares are quadrilaterals not all quadrilaterals are squares or rectangles.
Multiply the two numbers
26ft = how many inches Take away the piece of string with no lights (the 16 inches) See what's left and divide by 4 inches (as each light is placed 4 inches apart). Add 1 at the end as you didn't include the first bulb.
Find out what length of the string will have lights on it (some of it has no lights on it as said in the question). See how many 4 inches are then in that space. Don't forget to include the first bulb after you work out the total.
Well a square must have 4 equal sides. A rectangle doesn't have to. Following on from Ms. Sue, While you can say a square is always a rectangle, a rectangle isn't always a square.
Find 1 Mol of NaCl (using the periodic table) That amount of g in 1 litre of water is a 1.0 Mol/L solution of NaCl (that is its molarity) Compare that to what you have per litre
probability = (number of favourable outcomes)/(total number of outcomes) total outcomes = 3+6+4 = 13 Question 1: probability tiger = 3/13 then probability bear = 6/12 (as one from the 13 has been picked) then probability dog = 4/11 (as another from the
You have 12/52 for the first choice, 11/51 for the second and 10/50 for the third. Just multiply the three probabilities. MathMate, your instructions are incorrect for the question asked. C(52,12) is the number of combinations of 12 different cards that
Find the two factors using the roots (the intercepts) and then test the point (3,6) in your answer to see if you need to change the sign of everything.
Devron is right, I didn't notice the kj added in there instead of j. Your caluclation was correct just off by a factor of 1000 as a result. My apologies for not noticing.
You're welcome Jackie. Steve is right about the discriminant being incorrect by the way. x^2 + y^2 = 25 y = x - k x^2 + x^2 - 2xk +k^2 = 25 2x^2 - 2xk + k^2 - 25 = 0 x = 2k +- Sqrt(4k^2 - 4(2)(k^2 - 25)))/4 your discriminant is -4k^2 + 200
Looks right to me
Work = change in Kinetic Energy (units are Joules) KE = (1/2)*m*v^2 m = mass in kg v = velocity in m/s Power = work/time (units are Watts)
No, no it asks you for the values of k that let you get 2pts or 1pt or 0pts. You have to solve each of those. E.g. 100 - 4k^2 = 0 100 = 4k^2 25 = k^2 5 = k So, when k = 5 you get only 1 point 100 - 4k^2 > 0 100 > 4k^2 25 > k^2 5 > k So, when k > 5 you get
KE = (1/2)*m*v^2 m = mass (in kg) v = velocity (in m/s) Work = Change in KE but it starts at 0 so it's the KE you worked out - 0 Which looks to be the same as the first part and they have the same units too, joules.
if 100 - 4k^2 > 0 then you get 2 points if 100 - 4k^2 = 0 then you get 1 point if 100 - 4k^2 < 0 then you get 0 points
