A pyramid 8cm high stands on a rectangular base 6cm by 4cm. Calculate the volume of the pyramid
Volume=1/3*(6cm*4cm)*8cm
=64cm^3
V=1/3 times6cm^2 times4cm times8cm=64cm^3
from Prthogoras' theorem
DB^2=(6cm)^2+(4cm)^2
=36^2+16^2
oB^2=52cm^2
Find the square root of 52cm^2=
DB=7.21cm
XB=7.21/2=36.1cm
To calculate the volume of a pyramid, you can use the formula:
Volume = (base area × height) / 3
First, let's find the base area. Since the base of the pyramid is rectangular, the formula for the area is:
Area = length × width
In this case, the length is 6cm and the width is 4cm, so the base area is:
Area = 6cm × 4cm = 24cm²
Next, we can substitute the values into the volume formula:
Volume = (24cm² × 8cm) / 3
Now, let's calculate the volume:
Volume = (192cm²) / 3
To divide by 3, we can divide 192 by 3:
Volume = 64cm²
Therefore, the volume of the pyramid is 64 cubic centimeters (cm³).
Like it
Volume of all "pointy" things = (1/3)(area of the base)(height)
you have the data.
let me know what you get so I can check it
There seems to be an error in your calculation. Here's the correct solution:
Using the formula V = (1/3) * base area * height, where base area = length * width:
V = (1/3) * 6cm * 4cm * 8cm
V = 64 cm^3
Therefore, the volume of the pyramid is 64 cm^3.
For the second part of the problem:
Using the Pythagorean theorem, we have:
DB = sqrt((6cm)^2 + (4cm)^2)
DB = sqrt(36cm^2 + 16cm^2)
DB = sqrt(52cm^2)
DB = 7.2111cm (rounded to 4 decimal places)
Since D is the midpoint of XB, we have:
XB = 2 * DB
XB = 2 * 7.2111cm
XB = 14.4222cm (rounded to 4 decimal places)
Therefore, XB is approximately 14.4222cm.
16c+20
C=20-16
=4
That is correct.
If you have an expression 16c + 20 and you need to evaluate it when c = 4, you would substitute 4 in place of c to get:
16(4) + 20 = 64 + 20 = 84