A metallic pipe is 0.7 cm thick .Inner radius of the pipe is 3.5 cm and length is 5dm .Find it's total surface area?
that would be the area of the inner cylinder, plus the area of the outer cylinder, plus the area of the two rings at the end. So, if
R = outer radius
r = inner radius
h = length of pipe
the total area is
2πrh + 2πRh + π(R^2-r^2)
= 2πh(r+R) + π(R+r)(R-r)
= π(R+r)(2h+R-r)
Total surface area = inner curved surface area + outer curved surface area + area of 2 rings
We will consider ,
R=outer curved surface area
r=inner curved surface area
h=given lenght
=2πRh + 2πrh + πR^2 + πr^2
=π(r +R )+(2h + R-r )
After solving with values we will get the total surface area as 253.88 cm ^2
In above sum R = outer radius
r= inner radius
Sorry for the mistake
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