Find the absolute value of the resulting error if the value of integral from 0 to 3 (x^3 dx) is estimated with 3 trapezoids of equal width.
a) 2.25
b) 5.25
c) 15.75
d) 47.25
0 to 1
1 to 2 all of width 1
2 to 3
y(0) = 0
y(1) = 1
y(2) = 8
y(3) = 27
(1/2)(1+0) = .5
(1/2)(1+8) = 4.5
(1/2)(8+27) = 35/2 = 17.5
sum = 22.5
now do it perffecctly :)
y^4/4 at 3 minus at 0
81 /3 = 27