A force of 10 N causes aspring to extend by 20mm find the spring constant of the spring in N/m
10 =k x
and
x = 20 * 10^-3 meter
x = (10 /20)10^3 = .5 * 10^3 = 500 N/m
k = 10N /0.02m = 500 N/m.
THANKS FOR DAMON AND HENRY2
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10N/0.02M=500N/M
A force of 10 N causes a spiring to extend by 20 mm. Find the force applied that causes an extension of 5mm.
Information on the following information
k 200
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