The letter tiles C, A, R, E, S are placed in a box. Without looking, Jorelle picks a letter tile from the box and records the result before placing it back. If he repeats the procedure 100 times, how many times will the letter A tile be picked?
Since Jorelle places each letter tile back in the box before drawing again, the probability of drawing a letter A tile on any given draw is 1/5. Thus, if Jorelle repeats the procedure 100 times, we can expect him to draw the letter A tile approximately (1/5) x 100 = 20 times. Therefore, the letter A tile will be picked 20 times.
Since each outcome is equally likely to occur with a probability of 1/3, the probability of picking number 2 or 3 is:
P(2 or 3) = P(2) + P(3)
P(2 or 3) = 1/3 + 1/3
P(2 or 3) = 2/3
Therefore, the probability of picking number 2 or 3 is 2/3.
There are a total of 6 letter tiles in the box. Of these 6 letter tiles, there are 2 vowels (I and O) and 4 consonants (W, S, D, and M).
The probability of picking a vowel is equal to the number of vowels divided by the total number of letter tiles:
Probability of picking a vowel = number of vowels / total number of letter tiles
Probability of picking a vowel = 2 / 6
Simplifying the fraction, we get:
Probability of picking a vowel = 1/3
Therefore, the probability of picking a vowel is 1/3.
If there are 40 marbles in the bag and the marbles are identical in number, then we can divide the 40 marbles evenly among the five colors:
40 total marbles / 5 colors = 8 marbles of each color.
Therefore, there are 8 marbles of each color in the bag.
I apologize for my earlier mistake. You are correct that if Jorelle repeats the procedure 100 times, and each time he selects a letter tile from the box at random and replaces it, then the probability of picking the letter A on any given trial is 1/5.
Using the concept of expected value, we can expect to see the letter A appear approximately (1/5) x 100 = 20 times.
Therefore, we can expect the letter A to be picked 20 times in this scenario.
Thank you for bringing this to my attention.
In this sample space, the consonants are b, c, d, f. There are 4 consonants out of a total of 6 letters in the sample space.
Therefore, the probability of picking a consonant is 4/6, which simplifies to 2/3 in simplest form.
So, the probability of picking a consonant is 2/3.