To show how to solve the equation, create two functions and find their intersection points. What two functions can be used to solve the following equation, and what is their solution set?
x^2+4x−1=2x+2
(1 point)
Responses
f(x)=x^2+4x−1, g(x)=2x+2, {−3,1}
f left parenthesis x right parenthesis equals x squared plus 4 x minus 1 , g left parenthesis x right parenthesis equals 2 x plus 2 , left brace negative 3 comma 1 right brace
f(x)=x^2+4x, g(x)=2x, {−3,1}
f left parenthesis x right parenthesis equals x squared plus 4 x , g left parenthesis x right parenthesis equals 2 x , left brace negative 3 comma 1 right brace
f(x)=x^2+4x−1, g(x)=2x+2, {−1,3}
f left parenthesis x right parenthesis equals x squared plus 4 x minus 1 , g left parenthesis x right parenthesis equals 2 x plus 2 , left brace negative 1 comma 3 right brace
f(x)=x^2+4x−1, g(x)=2x+2, {−3,−4,1,4}
f(x)=x^2+4x−1, g(x)=2x+2, {−3,1}
The solution set to the equation x^2+4x−1=2x+2 is {-3, 1}. These are the x-values where the two functions intersect.