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An informative depiction of a parallel electrical circuit. The circuit contains two resistors: one resistor is of 20 ohms, it is cylindrical with a body of blue color and silver stripes, while the second is a 10-ohm resistor, also cylindrical but with a pink body and black stripes. Both resistors are arranged in parallel, plugged into a breadboard. The wires connecting them are color-coded: red for the positive feed, black for the ground. Additional elements include battery connections, but the whole setup is kept simple and neat for ease of understanding. No text is present in this image.

A parallel circuit with a 20-ohm resistor and a 10-ohm resistor.

let R equal total resistance

1/R = 1/20 + 1/10 = 3/20

R = 20/3 Ω

But is there anyway u can explain the equation. like how does 1/20 + 1/10 = 3/20

To find the total resistance in a parallel circuit, you use the formula:

1/RTotal = 1/R1 + 1/R2 + 1/R3 + ...

In your case, you have a parallel circuit with a 20-ohm resistor (R1) and a 10-ohm resistor (R2). So, the total resistance (RTotal) can be calculated as:

1/RTotal = 1/20 + 1/10

To simplify the calculation, you can calculate the common denominator:

1/RTotal = 1/20 + 2/20
= 3/20

Now, you can take the reciprocal of both sides to get RTotal:

RTotal = 20/3 ohms

Therefore, the total resistance in the given parallel circuit is approximately 6.67 ohms.

Thank you for the answer, but how come you didn't finish simplifying the problem!? Wouldn't you get 6.66666667 or something like that!?

When you divide 20 by 3, then yes, you will get 6.66666667. To get a decimal from a fraction, you will have to divide the numerator by the denominator.

I don't know but I like apples. :)

Why did the parallel circuit go to therapy? Because it had some serious resistance issues! With a 20-ohm resistor and a 10-ohm resistor, those components just couldn't agree on anything. They needed professional help to figure out how to coexist peacefully!