The letter tiles C, A, R, E, S are placed in a box. Without looking, Jorelle picks a letter tile from the box and records the result before placing it back. If he repeats the procedure 100 times, how many times will the letter A tile be picked?
Since Jorelle places each letter tile back in the box before drawing again, the probability of drawing a letter A tile on any given draw is 1/5. Thus, if Jorelle repeats the procedure 100 times, we can expect him to draw the letter A tile approximately (1/5) x 100 = 20 times. Therefore, the letter A tile will be picked 20 times.
If there are 40 marbles in the bag and the marbles are identical in number, then we can divide the 40 marbles evenly among the five colors:
40 total marbles / 5 colors = 8 marbles of each color.
Therefore, there are 8 marbles of each color in the bag.
There are a total of 6 letter tiles in the box. Of these 6 letter tiles, there are 2 vowels (I and O) and 4 consonants (W, S, D, and M).
The probability of picking a vowel is equal to the number of vowels divided by the total number of letter tiles:
Probability of picking a vowel = number of vowels / total number of letter tiles
Probability of picking a vowel = 2 / 6
Simplifying the fraction, we get:
Probability of picking a vowel = 1/3
Therefore, the probability of picking a vowel is 1/3.
Since each outcome is equally likely to occur with a probability of 1/3, the probability of picking number 2 or 3 is:
P(2 or 3) = P(2) + P(3)
P(2 or 3) = 1/3 + 1/3
P(2 or 3) = 2/3
Therefore, the probability of picking number 2 or 3 is 2/3.
I apologize for my earlier mistake. You are correct that if Jorelle repeats the procedure 100 times, and each time he selects a letter tile from the box at random and replaces it, then the probability of picking the letter A on any given trial is 1/5.
Using the concept of expected value, we can expect to see the letter A appear approximately (1/5) x 100 = 20 times.
Therefore, we can expect the letter A to be picked 20 times in this scenario.
Thank you for bringing this to my attention.
In this sample space, the consonants are b, c, d, f. There are 4 consonants out of a total of 6 letters in the sample space.
Therefore, the probability of picking a consonant is 4/6, which simplifies to 2/3 in simplest form.
So, the probability of picking a consonant is 2/3.