What is the distance between (19, -6) and (8, -6) on a coordinate plane?
The distance between two points (x1, y1) and (x2, y2) on a coordinate plane can be calculated using the distance formula:
Distance = √((x2 - x1)^2 + (y2 - y1)^2)
In this case, the points are (19, -6) and (8, -6).
Plugging in the values:
Distance = √((8 - 19)^2 + (-6 - (-6))^2)
Distance = √((-11)^2 + 0^2)
Distance = √(121 + 0)
Distance = √121
Distance = 11
Therefore, the distance between (19, -6) and (8, -6) on a coordinate plane is 11 units.